说明

Calculate a+b

输入格式

Two integer a,b (0<=a,b<=10)

输出格式

Output a+b

样例

1 2

3

提示

#include <stdio.h>

int main()

{

    int a,b;

    while(scanf("%d %d",&a, &b) != EOF)

        printf("%d\n",a+b);

    return 0;

}

#include <iostream>

using namespace std;

int main()

{

    int a,b;

    while(cin >> a >> b)

        cout << a+b << endl;

}

program p1001(Input,Output);

var

  a,b:Integer;

begin

   while not eof(Input) do

     begin

       Readln(a,b);

       Writeln(a+b);

     end;

end.

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {

        Scanner in = new Scanner(System.in);

        while (in.hasNextInt()) {

            int a = in.nextInt();

            int b = in.nextInt();

            System.out.println(a + b);

        }

    }

}

a=gets.chomp

b="0"

a.each_line(" "){

|d|

b=b+"+"+d

}

puts eval(b)

read a b

echo $(($a+$b))

import sys

for line in sys.stdin:

    a = line.split()

    print int(a[0]) + int(a[1])

<?php

while (fscanf(STDIN, "%d%d", $a, $b) == 2) {

    print ($a + $b) . "\n";

}

?>

#! /usr/bin/perl -w

while(<>){

  chomp;

  ($a,$b)=split(/\s/,$_);

  printf "%d\n",$a+$b;

}

using System;

public class Sum

{

    public static void Main()

    {

        //string token = Console.ReadLine();

        //int test = int.Parse(token);

        for(int k = 0; k < 1;k++){

             string[] tokens = Console.ReadLine().Split(' ');

         Console.WriteLine(int.Parse(tokens[0]) + int.Parse(tokens[1]));

    }

    }

}